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-x^2+6x+28=0
We add all the numbers together, and all the variables
-1x^2+6x+28=0
a = -1; b = 6; c = +28;
Δ = b2-4ac
Δ = 62-4·(-1)·28
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{37}}{2*-1}=\frac{-6-2\sqrt{37}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{37}}{2*-1}=\frac{-6+2\sqrt{37}}{-2} $
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